#Artificial Intelligence
Tic Tac Toe Puzzle : An Artificially Intelligent Approach Using Min-Max Algorithm
I really enjoyed coding this animated game with my project partner Yulia. You can post your questions if any clarification required.
--------------------------------------------------------------
The Heuristic for Min-Max Game Strategy :
Return difference between winning options for X and winning options for O,
E(P) = N(X) - N(O)
check every row, column and diagonal for winning option
accumulate total score for each player and find the difference
if there are any X and O on the same row/column/diagonal - score = 0
if there are 2 X/O (depends on player) - score increased on 100
if there are 3 X/O (depends on player) - score increadsed on 1000
---------------------------------------------------------------
First File : TicTacToeHelper.Java
package game;
import java.util.ArrayList;
public class TicTacToeHelper {
public int current_score;
public int cntX;
public int cntO;
public int scoreX;
public int scoreO;
public static final Integer[] row1 = { 0, 1, 2 };
public static final Integer[] row2 = { 3, 4, 5 };
public static final Integer[] row3 = { 6, 7, 8 };
public static final Integer[] column1 = { 0, 3, 6 };
public static final Integer[] column2 = { 1, 4, 7 };
public static final Integer[] column3 = { 2, 5, 8 };
public static final Integer[] diagonal1 = { 0, 4, 8 };
public static final Integer[] diagonal2 = { 6, 4, 2 };
/*
* return difference between winning options for X and winning options for O
* E(P) = N(X) - N(O)
* check every row, column and diagonal for winning option
* accumulate total score for each player and find the difference
* if there are any X and O on the same row/column/diagonal - score = 0
* if there are 2 X/O (depends on player) - score increased on 100
* if there are 3 X/O (depends on player) - score increadsed on 1000
*
*/
public int heuristic_score(ArrayList<Integer> boardcopy) {
// get score E = N(X) - N(O)
scoreX = 0;
scoreO = 0;
//check row1
cntX = get_score(boardcopy, row1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row1, 2);
scoreO = scoreO + cntO;
//check row2
cntX = get_score(boardcopy, row2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row2, 2);
scoreO = scoreO + cntO;
//check row3
cntX = get_score(boardcopy, row3, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row3, 2);
scoreO = scoreO + cntO;
//check column1
cntX = get_score(boardcopy, column1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column1, 2);
scoreO = scoreO + cntO;
//check column2
cntX = get_score(boardcopy, column2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column2, 2);
scoreO = scoreO + cntO;
//check column3
cntX = get_score(boardcopy, column3, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column3, 2);
scoreO = scoreO + cntO;
//check diagonal1
cntX = get_score(boardcopy, diagonal1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, diagonal1, 2);
scoreO = scoreO + cntO;
//check diagonal2
cntX = get_score(boardcopy, diagonal2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, diagonal2, 2);
scoreO = scoreO + cntO;
current_score = scoreX - scoreO;
//System.out.println(" current score = "+ current_score+" : scoreX - ScoreO = "+ scoreX +" - "+scoreO );
return current_score;
}
/*
* returns true if plaeyr has 3 X or O on row/column/diagonal,
* othervise, return false
*/
public boolean check_winner(ArrayList<Integer> boardcopy, int player)
{
int cnt = 0;
//check row1
cnt = get_score(boardcopy, row1, player);
if(cnt>=1000)
return true;
//check row2
cnt = get_score(boardcopy, row2, player);
if(cnt>=1000)
return true;
//check row3
cnt = get_score(boardcopy, row3, player);
if(cnt>=1000)
return true;
//check column1
cnt = get_score(boardcopy, column1, player);
if(cnt>=1000)
return true;
//check column2
cnt = get_score(boardcopy, column2, player);
if(cnt>=1000)
return true;
//check column3
cnt = get_score(boardcopy, column3, player);
if(cnt>=1000)
return true;
//check diagonal1
cnt = get_score(boardcopy, diagonal1, player);
if(cnt>=1000)
return true;
//check diagonal2
cnt = get_score(boardcopy, diagonal2, player);
if(cnt>=1000)
return true;
return false;
}
/*
* returns score for player(X or O) for specific row/column/diagonal
* if there are any X and O on the same row/column/diagonal - score = 0
* if there are 2 X/O (depends on player) - score = 100
* if there are 3 X/O (depends on player) - score = 1000
*
*/
public int get_score(ArrayList<Integer> arrcopy, Integer [] comp, int player)
{
//check any possible winner option for X and O
// X=1; O=2;
int score = 0;
int cnt1 = 0;
int cnt2 = 0;
for(Integer r:comp )
{
if(arrcopy.get(r)==1)
cnt1++;
if(arrcopy.get(r)==2)
cnt2++;
}
if(cnt1 !=0 && cnt2 != 0)
{// O and X on the same row
cnt1 = 0;
cnt2 = 0;
score = 0;
return score;
}
else // no X and O at the same row/column/diagonal
{
if(player == 1) // X
{
score = cnt1;
if(cnt1==2)
score = 100;
if(cnt1==3)
score = 1000;
}
if(player == 2) // O
{
score = cnt2;
if(cnt2==2)
score = 100;
if(cnt2==3)
score = 1000;
}
}
return score;
}
//print board
public void print_board(ArrayList<Integer> board)
{
System.out.println(" -------");
System.out.println(" |"+board.get(0)+"|"+ board.get(1)+"|"+board.get(2)+"|");
System.out.println(" -------");
System.out.println(" |"+board.get(3)+"|"+ board.get(4)+"|"+board.get(5)+"|");
System.out.println(" -------");
System.out.println(" |"+board.get(6)+"|"+ board.get(7)+"|"+board.get(8)+"|");
System.out.println(" -------");
}
}
--------------------------------------------------------------------------
Second File : TicTacToeMinMax.Java
Tic Tac Toe Puzzle : An Artificially Intelligent Approach Using Min-Max Algorithm
I really enjoyed coding this animated game with my project partner Yulia. You can post your questions if any clarification required.
--------------------------------------------------------------
The Heuristic for Min-Max Game Strategy :
Return difference between winning options for X and winning options for O,
E(P) = N(X) - N(O)
check every row, column and diagonal for winning option
accumulate total score for each player and find the difference
if there are any X and O on the same row/column/diagonal - score = 0
if there are 2 X/O (depends on player) - score increased on 100
if there are 3 X/O (depends on player) - score increadsed on 1000
---------------------------------------------------------------
First File : TicTacToeHelper.Java
package game;
import java.util.ArrayList;
public class TicTacToeHelper {
public int current_score;
public int cntX;
public int cntO;
public int scoreX;
public int scoreO;
public static final Integer[] row1 = { 0, 1, 2 };
public static final Integer[] row2 = { 3, 4, 5 };
public static final Integer[] row3 = { 6, 7, 8 };
public static final Integer[] column1 = { 0, 3, 6 };
public static final Integer[] column2 = { 1, 4, 7 };
public static final Integer[] column3 = { 2, 5, 8 };
public static final Integer[] diagonal1 = { 0, 4, 8 };
public static final Integer[] diagonal2 = { 6, 4, 2 };
/*
* return difference between winning options for X and winning options for O
* E(P) = N(X) - N(O)
* check every row, column and diagonal for winning option
* accumulate total score for each player and find the difference
* if there are any X and O on the same row/column/diagonal - score = 0
* if there are 2 X/O (depends on player) - score increased on 100
* if there are 3 X/O (depends on player) - score increadsed on 1000
*
*/
public int heuristic_score(ArrayList<Integer> boardcopy) {
// get score E = N(X) - N(O)
scoreX = 0;
scoreO = 0;
//check row1
cntX = get_score(boardcopy, row1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row1, 2);
scoreO = scoreO + cntO;
//check row2
cntX = get_score(boardcopy, row2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row2, 2);
scoreO = scoreO + cntO;
//check row3
cntX = get_score(boardcopy, row3, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, row3, 2);
scoreO = scoreO + cntO;
//check column1
cntX = get_score(boardcopy, column1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column1, 2);
scoreO = scoreO + cntO;
//check column2
cntX = get_score(boardcopy, column2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column2, 2);
scoreO = scoreO + cntO;
//check column3
cntX = get_score(boardcopy, column3, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, column3, 2);
scoreO = scoreO + cntO;
//check diagonal1
cntX = get_score(boardcopy, diagonal1, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, diagonal1, 2);
scoreO = scoreO + cntO;
//check diagonal2
cntX = get_score(boardcopy, diagonal2, 1);
scoreX = scoreX + cntX;
cntO = get_score(boardcopy, diagonal2, 2);
scoreO = scoreO + cntO;
current_score = scoreX - scoreO;
//System.out.println(" current score = "+ current_score+" : scoreX - ScoreO = "+ scoreX +" - "+scoreO );
return current_score;
}
/*
* returns true if plaeyr has 3 X or O on row/column/diagonal,
* othervise, return false
*/
public boolean check_winner(ArrayList<Integer> boardcopy, int player)
{
int cnt = 0;
//check row1
cnt = get_score(boardcopy, row1, player);
if(cnt>=1000)
return true;
//check row2
cnt = get_score(boardcopy, row2, player);
if(cnt>=1000)
return true;
//check row3
cnt = get_score(boardcopy, row3, player);
if(cnt>=1000)
return true;
//check column1
cnt = get_score(boardcopy, column1, player);
if(cnt>=1000)
return true;
//check column2
cnt = get_score(boardcopy, column2, player);
if(cnt>=1000)
return true;
//check column3
cnt = get_score(boardcopy, column3, player);
if(cnt>=1000)
return true;
//check diagonal1
cnt = get_score(boardcopy, diagonal1, player);
if(cnt>=1000)
return true;
//check diagonal2
cnt = get_score(boardcopy, diagonal2, player);
if(cnt>=1000)
return true;
return false;
}
/*
* returns score for player(X or O) for specific row/column/diagonal
* if there are any X and O on the same row/column/diagonal - score = 0
* if there are 2 X/O (depends on player) - score = 100
* if there are 3 X/O (depends on player) - score = 1000
*
*/
public int get_score(ArrayList<Integer> arrcopy, Integer [] comp, int player)
{
//check any possible winner option for X and O
// X=1; O=2;
int score = 0;
int cnt1 = 0;
int cnt2 = 0;
for(Integer r:comp )
{
if(arrcopy.get(r)==1)
cnt1++;
if(arrcopy.get(r)==2)
cnt2++;
}
if(cnt1 !=0 && cnt2 != 0)
{// O and X on the same row
cnt1 = 0;
cnt2 = 0;
score = 0;
return score;
}
else // no X and O at the same row/column/diagonal
{
if(player == 1) // X
{
score = cnt1;
if(cnt1==2)
score = 100;
if(cnt1==3)
score = 1000;
}
if(player == 2) // O
{
score = cnt2;
if(cnt2==2)
score = 100;
if(cnt2==3)
score = 1000;
}
}
return score;
}
//print board
public void print_board(ArrayList<Integer> board)
{
System.out.println(" -------");
System.out.println(" |"+board.get(0)+"|"+ board.get(1)+"|"+board.get(2)+"|");
System.out.println(" -------");
System.out.println(" |"+board.get(3)+"|"+ board.get(4)+"|"+board.get(5)+"|");
System.out.println(" -------");
System.out.println(" |"+board.get(6)+"|"+ board.get(7)+"|"+board.get(8)+"|");
System.out.println(" -------");
}
}
--------------------------------------------------------------------------
Second File : TicTacToeMinMax.Java
package game;
import java.applet.Applet;
import java.awt.Color;
import java.awt.Dimension;
import java.awt.Graphics;
import java.util.ArrayList;
/*
* Include My Name If you Use this Code....
*
* Max move first
* X - max level
* O - min level
* presentation of X = 1
* presentation of O = 2
* board presentation:
* row1 = { 0, 1, 2 };
* row2 = { 3, 4, 5 };
* row3 = { 6, 7, 8 };
* column1 = { 0, 3, 6 };
* column2 = { 1, 4, 7 };
* column3 = { 2, 5, 8 };
* diagonal1 = { 0, 4, 8 };
* diagonal2 = { 6, 4, 2 };
*/
public class TicTacToeMinMax extends Applet {
boolean x_turn= true;
boolean o_turn;
static boolean winner = false;
int player = 1;
boolean level_min;
boolean level_max = true;
int max_depth = 3;
int min_depth = 2;
int depth;
int current_score;
int score_depth2;
int score_depth1;
int score_depth0;
int level_score;
int best_move;
int cntX;
int cntO;
int scoreX;
int scoreO;
Dimension d = new Dimension(200, 200);
ArrayList<Integer> board = new ArrayList<Integer>(9);
ArrayList<Integer> boardcopy = new ArrayList<Integer>(9);
//int[] board = new int[9];
//initialize board with alll positions 0
public TicTacToeMinMax()
{
for(int c=0; c<9; c++)
{
board.add(0);
}
}
/*
* moveX return the best position for X using minmax algorithm and
* go deep on 3 levels of children to bring the best move position on board for X
* presentation: X = 1; O = 2
* X move first
* depth0: Max level - current state of board - expect the best move of X
* depth1: Min level - X turn: X try move to any available position on board
* depth2: Max level - O turn: for every possible X turn, O will try to find the best spot for O
* depth3: Min level - X turn: try to find the best position- block O from winning or win
*
* on last childrens level (depth3) calculate score for every child, select maximum score for X, percolate this score to level Max, depth 2
* for depth1 percolate minimum of bringing scores from depth2 level, as soon as player O - minimum
* then percolate the maximum of depth1 children to depth0 max level, since it was max level - select the biggest scored child
* position of this child is the best move for player X
*/
public int moveX(ArrayList<Integer> current_board)
{
TicTacToeHelper help = new TicTacToeHelper();
level_max = true;
player = 1;
depth = max_depth;
x_turn = true;
best_move = 0;
score_depth2 = 0;
score_depth1 = 0;
score_depth0 = 0;
//depth 0: initial state of board current_board; max level
int cnt0 = 0;
for(int i=0; i < 9; i++) //current depth = 1; MIN level, X turn, player X
{
//for every empty spot on board check possible X position
level_score=0;
if(current_board.get(i)==0)
{ //make a copy of current board
boardcopy.clear();
boardcopy.addAll(current_board);
boardcopy.set(i, new Integer(1));
cnt0++;
// to get score - go level down - generate children
// for every possible move - generate children
int cnt1 = 0;
for(int k = 0; k < 9; k++) //current depth = 2; MAX level, O turn, O=2, player O
{
if(boardcopy.get(k)==0)
{
//possible position for O
boardcopy.set(k, new Integer(2));
cnt1++;
// to get score - go level down - generate children
// for every possible move - generate children
int cnt2 = 0;
for(int x= 0; x < 9; x++) //current depth = 3; MIN level, X turn, X=1, player X
{
if(boardcopy.get(x)==0)
{
//possible position for X
boardcopy.set(x, new Integer(1));
cnt2++;
// depth 3 - now get score
// get score E(P) = N(X) - N(O)
// score_depth3 = current_score
current_score = help.heuristic_score(boardcopy);
// System.out.println("depth3: x["+x+"] = "+ current_score);
//to percolate score on next depth2 MAX level choose the biggest score - MAX
if(cnt2==1) //first child score
score_depth2 = current_score;
else
{
if
(score_depth2 < current_score) // bring the biggest score for X
score_depth2 = current_score;
}
// System.out.println("depth2: score for k["+k+"] = "+score_depth2);
//clear position from copy after evaluation
boardcopy.set(x, new Integer(0));
}
}
// keep MIN score, move to the next child node
//to percolate score on next depth1 MIN level choose the smallest score - MIN
if(cnt1==1) //first child score
score_depth1 = score_depth2 ;
else
{
if
(score_depth1 > score_depth2 ) // bring the smallest score for O
score_depth1 = score_depth2 ;
}
// System.out.println("depth1: score for i["+i+"] = "+score_depth1);
//clear position from copy after evaluation
boardcopy.set(k, new Integer(0)); // clear position after evaluation is done
}
} // end of depth2
// get MAX score for X depth0
//to percolate score on next depth0 MAX level choose the biggest score - MAX
if(cnt0==1) //first child score
{
score_depth0 = score_depth1;
best_move = i;
}
else
{
if(score_depth0 < score_depth1) // bring the biggest score for X
{
score_depth0 = score_depth1;
best_move = i;
}
}
//System.out.println("X: depth0: score for i["+i+"] = "+score_depth0);
// removed possible position from copy of board
boardcopy.set(i, new Integer(0));
}
} // end of depth1
return best_move; // depth0
}
// O move-----------------------------------------------------------------------------
/*
* moveO return the best position for O using minmax algorithm and
* go deep on 2 levels of children to bring the best move position on board for X
* presentation: X = 1; O = 2
*
* depth0: Min level - current state of board - expect the best move of O
* depth1: Max level - O turn: O try move to any available position on board
* depth2: Min level - X turn: X will try to find the best spot for X
*
* on last children level (depth2) calculate score for every child, select minimum score for O, percolate this score to level Min, depth 1
* for depth1 percolate minimum of bringing scores from depth2 level, as soon as player O - minimum
* then percolate the maximum of depth1 children to depth0 max level, since it was max level - select the biggest scored child
* position of this child is the best move for player O
*/
public int moveO(ArrayList<Integer> current_board)
{
TicTacToeHelper help = new TicTacToeHelper();
player = 2;
depth = min_depth; //2
o_turn = true;
best_move = 0;
score_depth2 = 0;
score_depth1 = 0;
score_depth0 = 0;
//depth 0: initial state of board current_board; max level
int cnt0 = 0;
for(int i=0; i < 9; i++) //current depth = 1; MIN level, O turn, player O
{
//for every empty spot on board check possible O position
level_score=0;
if(current_board.get(i)==0)
{ //make a copy of current board
boardcopy.clear();
boardcopy.addAll(current_board);
boardcopy.set(i, new Integer(2));
cnt0++;
// to get score - go level down - generate children
// for every possible move - generate children
int cnt1 = 0;
for(int k = 0; k < 9; k++) //current depth = 2; MAX level, O turn, O=2, player O
{
if(boardcopy.get(k)==0)
{
//possible position for O
boardcopy.set(k, new Integer(1));
cnt1++;
// get score E(P) = N(X) - N(O)
// score_depth2 = current_score
current_score = help.heuristic_score(boardcopy);
// keep MAX score, move to the next child node
//to percolate score on next depth1 MIN level choose the smallest score - MIN
if(cnt1==1) //first child score
score_depth1 = current_score;
else
{
if(score_depth1 < current_score) // bring the biggest score for X
score_depth1 = current_score;
}
//clear position from copy after evaluation
boardcopy.set(k, new Integer(0)); // clear position after evaluation is done
}
} // end of depth2
// get MAX score for O depth0
//to percolate score on next depth0 MIN level choose the biggest score - MIN
if(cnt0==1) //first child score
{
score_depth0 = score_depth1;
best_move = i;
}
else
{
if(score_depth0 > score_depth1) // bring the biggest score for X
{
score_depth0 = score_depth1;
best_move = i;
}
}
//System.out.println("O: depth0: score for i["+i+"] = "+score_depth0);
// removed possible position from copy of board
boardcopy.set(i, new Integer(0));
}
} // end of depth1
return best_move; // depth0
}
public void init() {
super.init();
setBackground(Color.white);
//{{INIT_CONTROLS
setLayout(null);
resize(500,200);
//}}
}
public void paint(Graphics g)
{
TicTacToeMinMax m = new TicTacToeMinMax();
TicTacToeHelper help = new TicTacToeHelper();
int position = 0;
// System.out.println("X move first .........................................");
while(m.board.contains(0) && !winner)
{
int i, j;
int xoff = d.width / 3;
int yoff = d.height / 3;
for (i = 0; i < 3; i++)
{
for (j = 0; j < 3; j++)
{
g.setColor(Color.black);
g.drawRect(j * xoff + 2, i * yoff + 2, xoff - 4, yoff - 4);
}
}
//max move first
// System.out.println("\nit is X turn now .......................................");
position = m.moveX(m.board);
m.board.set(position, new Integer(1));
if(position <=2){
i=0;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawX(g, d, i, position);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else if(position>2 && position <=5){
i=1;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawX(g, d, i, position-3);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else{
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawX(g, d, 2, position-6);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
// System.out.println(".. X was moved to position "+position+" (first maximum was selected)");
help.print_board(m.board);
//check if X is winner
winner = help.check_winner(m.board, 1);
if(winner)
{
System.out.println(".. X won! End of game");
break;
}
//min move
if(m.board.contains(0))
{
// System.out.println("\nit is O turn now .......................................");
position = m.moveO(m.board);
m.board.set(position, new Integer(2));
if(position <=2){
i=0;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawO(g, d, i, position);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else if(position>2 && position <=5){
i=1;
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawO(g, d, i, position-3);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
else{
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
DrawO(g, d, 2, position-6);
try {
Thread.sleep(1000);
} catch (InterruptedException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
// System.out.println(".. O was moved to position: "+position+" (first minimum was selected)");
help.print_board(m.board);
//check if O is winner
winner = help.check_winner(m.board, 2);
if(winner)
{
System.out.println(".. O won! End of game");
break;
}
}
}
}
public void DrawX(Graphics g, Dimension d, int row, int col)
{
int xStart, yStart, xOff, yOff;
int i;
xOff = d.width / 3;
yOff = d.height / 3;
xStart = xOff * col;
yStart = yOff * row;
for (i = 0; i < 4; i++)
{
g.drawLine(xStart + i + 6, yStart + 6,
xStart + xOff + i - 10, yStart + yOff - 10);
g.drawLine(xStart + xOff + i - 10, yStart + 6,
xStart + i + 6, yStart + yOff - 10);
}
}
public void DrawO(Graphics g, Dimension d, int row, int col)
{
int xStart, yStart, xOff, yOff;
int i;
xOff = d.width / 3;
yOff = d.height / 3;
xStart = xOff * col;
yStart = yOff * row;
for (i = 0; i < 4; i++)
{
g.drawOval(xStart + i + 6, yStart + i + 6,
xOff - i * 2 - 10, yOff - i * 2 - 10);
}
}
}
--------------------------------------------------------------------------------
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